X^2-4x+9=5

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Solution for X^2-4x+9=5 equation: 



X^2-4X+9=5

We move all terms to the left:

X^2-4X+9-(5)=0

We add all the numbers together, and all the variables

X^2-4X+4=0

a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{4}{2}=2$

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